The perimeter of a rectangle is 56 units, and its length is 18 units. What is the width of the rectangle?
P=2×(length +width)
Given that the perimeter (P) of the rectangle is 56 units and the length is 18 units, we can substitute these values into the formula and solve for the width (W):
56 units=2×(18 units+width)
First, let's simplify the equation:
56 units=36 units+2×width
56 units−36 units=2×width
20 units=2×width
Now, let's divide both sides by 2 to isolate the width:
width=20/2 units
width=10 units
Therefore, the width of the rectangle is 10 units
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